Every square matrix is associated with a characteristic polynomial.
This polynomial encodes several important
properties of the matrix, most
notably its eigenvalues, its determinant and its trace.
Given a square matrix A, we want to find a polynomial whose zeros are the eigenvalues
of A. For a diagonal matrix A, the characteristic polynomial is
easy to define: if the diagonal entries are a1, a2, a3, etc. then the
characteristic polynomial will be: (t-a1)(t-a2)(t-a3)…
This works because the diagonal entries are also the
eigenvalues of this matrix.
For a general matrix A, one can proceed as follows. A scalar λ is an eigenvalue of A if and only if there is an eigenvector v ≠ 0 such that:
or
(where I is the identity matrix).
Since v is non-zero,
this means that the matrix λ I − A is singular (non-invertible), which in turn means that its determinant is
0. Thus the roots of the function det (λ I − A) are the eigenvalues of A, and it is clear that this determinant is a polynomial in λ.


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